*Can you crack the logic?*
Question of IIM-B
This is a very interesting and intelligent question..
If 1 1 1 1= 82 %
2 2 2 2= 80 %
3 3 3 3= 95 %
4 4 4 4= 86 %
Then
*5 5 5 5= ?*
Challenge to all master brains!
*Explain the answer with logic.*
Answers
Given : 1 1 1 1= 82 % , 2 2 2 2= 80 % , 3 3 3 3= 95 % , 4 4 4 4= 86 %
To find : 5 5 5 5 = ?
Solution:
1 1 1 1= 82 %
1 + 1 + 1 + 1 = FouR
R is 18th letter of A to Z
100 - 18 = 82
2 2 2 2= 80 %
2 +2 + 2 +2 = EighT
T is 20th letter of A to Z
100 - 20 = 80
3 3 3 3= 95 %
3 +3 + 3 +3 = TwelvE
E is 5th letter of A to Z
100 - 5 = 95
4 4 4 4= 86 %
4 +4 + 4 +4 = SixteeN
N is 14th letter of A to Z
100 - 14 = 86
5 5 5 5 =
5 +5 + 5 +5 = TwentY
Y is 25th letter of A to Z
100 - 25 = 75
=> 5 5 5 5 = 75 %
logic is : add all number and subtract equivalent value of last letter from 100
Learn more:
2,40, 180,552, 1110,1112 - Brainly.in
https://brainly.in/question/13391929
6+1=37 2+4=66 1+9=84 6+4
https://brainly.in/question/13072976
Answer:
75%
Step-by-step explanation: