Question

can you do the 2nd of this question​

Answer 1

Answer:

Step-by-step explanation:

a^3 + b^3 + c^3 - 3abc = (a+b+c) (a^2 + b^2 + c^2 - ab - bc -ca)

So if a+b+c = 0

then a^3 + b^3 + c^3 - 3abc = 0

So a^3 + b^3 + c^3 = 3abc