Math, asked by luciexforstudy837, 1 year ago

Can you draw a triangle with vertices (1,5) (5,8) and (13,14)

Answers

Answered by anahitasharma221035
1

Answer:

Step-by-step explanation:

Area of a triangle =  \frac{1}{2} | (x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) |  

=   \frac{1}{2} | 1(8-14) + 5(14-5) + 13(5-8) |  

=   \frac{1}{2} | 1(-6) + 5(9) + 13(-3) |

=   \frac{1}{2} | -6 + 45 - 39 |

=   \frac{1}{2} | 45 - 45 |

=   \frac{1}{2} | 0 |

=   \frac{0}{2}  = 0

The area of the triangle is equal to zero. So we can not form a triangle.  

The given points are collinear

1 and 5 = x1 and y1

5 and 8 =x2and y2

13 and 14 = x3 and y3

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