Can you draw a triangle with vertices (1, 5), (5, 8) and (13, 14)? Give reason.
Answers
Answered by
20
Hi ,
Let us assume , A ( 1 ,5 ) , B (5 , 8 ),
and C(13 ,14 ) are vertices of a triangle
ABC,
Now find the area of the triangle
ABC
Area
= 1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
=1/2|1(8-14)+5(14-5)+13(5-8)|
=1/2|(-6) + 5(9)+13 (-3) |
= 1/2 | -6 + 45 - 39 |
= 1 / 2 | -45 + 45 |
= 1/2 × 0
= 0
Therefore ,
Area of the triangle ABC = 0
It means A, B and C are not makes a
Triangle.
They are collinear points.
I hope this helps you.
:)
Let us assume , A ( 1 ,5 ) , B (5 , 8 ),
and C(13 ,14 ) are vertices of a triangle
ABC,
Now find the area of the triangle
ABC
Area
= 1/2|x1(y2-y3)+x2(y3-y1)+x3(y1-y2)|
=1/2|1(8-14)+5(14-5)+13(5-8)|
=1/2|(-6) + 5(9)+13 (-3) |
= 1/2 | -6 + 45 - 39 |
= 1 / 2 | -45 + 45 |
= 1/2 × 0
= 0
Therefore ,
Area of the triangle ABC = 0
It means A, B and C are not makes a
Triangle.
They are collinear points.
I hope this helps you.
:)
Answered by
0
The points are collinear
Hence triangle is not formed
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