Can you explain how it's 3.6?
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m1 of child=30 kg
its u1= 6m/s
m2 of cart=20kg
u2 of cart=0
Let after collision , their speed be v
According to law of conservation of momentum,
m1u1+m2u2=(m1+m2)v
30×6+20×0=(30+20)v
180=50v
v=180/50
therefore..v=3.6 m/s
its u1= 6m/s
m2 of cart=20kg
u2 of cart=0
Let after collision , their speed be v
According to law of conservation of momentum,
m1u1+m2u2=(m1+m2)v
30×6+20×0=(30+20)v
180=50v
v=180/50
therefore..v=3.6 m/s
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