Question

can you factorize ts 4x^4+81

Answer 1

Hay!!
dear user -

4x4+81

=> 4x4+81

=> 4x4+36x2+81-36x2

 => (2x2+9)2-(6x)2 

=> (2x2+9+6x)(2x2+9-6x)

I hope it's help you

Answer 2

The factorization of $4x^{4} +81$ is $(9+2x^{2} +6x)(9+2x^{2}-6x)$.

Step-by-step explanation:

We have,

$4x^{4} +81$

To find,$4x^{4} +81=?$

$81+4x^{4}$

We know that,

$x^4 + 4y^4 = (x^2+2y^2+ 2xy)(x^2+ 2y^2-2xy)$

∴ $3^{4}+4x^{4}$

$=(3^{2} +2x^{2} +2(3)x)(3^{2} +2x^{2} -2(3))$

$=(9+2x^{2} +6x)(9+2x^{2}-6x)$

Hence, the factorization of $4x^{4} +81$ is $(9+2x^{2} +6x)(9+2x^{2}-6x)$.