Physics, asked by ansafhaneef74, 8 hours ago

can you find the answer
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Answered by thealonewalker1678
1

Answer:

L.H.S dimension formula of T = [M^{0}L^{0}T^{1}]

R.H.S dimensions formula of 2π\sqrt{\frac{m}{g} }  = [M^{1}[L^{1}T^{-2}]^-1]^\frac{1}{2}

                                                            =  [M^{1}L^{-1}T^{2}]^\frac{1}{2}

                                                            = [M^{\frac{1}{2} }L^{\frac{-1}{2} }T^{1}]

L.H.S.= [M^{0}L^{0}T^{1}]

R.H.S.= [M^{\frac{1}{2} }L^{\frac{-1}{2} }T^{1}]

L.H.S.≠R.H.S.

Hence, the equation is dimensionally incorrect.

Explanation:

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