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HOPE IT HELPS.
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akirath:
thank for giving answer for my question
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Let diagonals are a &b
a+ b= 10
b= 10-a ............1)
area of rhombus= 12* product of diagonals
area = 1/2*ab ........2)
put value of b in 2)
area = 1/2*(10-a)*a
12*2= 10a-a*a
a*a-10a+24
a*a-6a-4a+24
a(a-6)-4(a-6)
a= 6 or 4
put value of a in 1)
a+b= 10
6+b= 10
b= 4
a+ b= 10
b= 10-a ............1)
area of rhombus= 12* product of diagonals
area = 1/2*ab ........2)
put value of b in 2)
area = 1/2*(10-a)*a
12*2= 10a-a*a
a*a-10a+24
a*a-6a-4a+24
a(a-6)-4(a-6)
a= 6 or 4
put value of a in 1)
a+b= 10
6+b= 10
b= 4
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