can you help me solve this?
54-32=25-
Answers
54-32=25-x
22=25-x
22-25=-x
-3=-x
THEREFORE, x=3 ( required answer )
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Correct question is "can you help me solve this? 54-32=25-x"
Answer:
Required solution is
Step-by-step explanation:
Given,
We are subtracting 32 from 54,
We are separating variable and constant part,
We are Subtracting 22 from 25 and get,
Required value of x is 3.
This is a problem of Algebra.
Some important Algebra formulas.
(a + b)² = a² + 2ab + b²
(a − b)² = a² − 2ab − b²
(a + b)³ = a³ + 3a²b + 3ab² + b³
(a - b)³ = a³ - 3a²b + 3ab² - b³
a³ + b³ = (a + b)³ − 3ab(a + b)
a³ - b³ = (a -b)³ + 3ab(a - b)
a² − b² = (a + b)(a − b)
a² + b² = (a + b)² − 2ab
a² + b² = (a − b)² + 2ab
a³ − b³ = (a − b)(a² + ab + b²)
a³ + b³ = (a + b)(a² − ab + b²)
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