Math, asked by lalalalala93, 1 year ago

can you please answer that question ​

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Answered by alvairis1995
0

Answer:

Step-by-step explanation:

sons present age = 10

sons age five yeas ago=5yrs substituting the value of x in equation.

y-2x+10

y=2*10+10

20+10

y=30yrs

women's present age = 30

Answered by aariztkhan
0

Answer:

Step-by-step explanation:

Six years ago let the son age = x

Mother's age = x² 

Present ages now:

Mother's age = x + 6

Mother's age = x²  + 6

3 years later:

Son's age = x + 6 + 3 = x + 9

Mother's age =  x²  + 6 + 3 =  x²  + 9 

x²  + 9 = 3(x + 9)

x²  + 9 = 3x + 27

x²  - 3x - 18 = 0

(x - 6)(x + 3) = 0

x = 6 or x = -3

Take x = 6. As the other value is negative which is not possible

Finding their Present age -

Son's age = x + 6 = 6 + 6 = 12 years.

Mother's age =  x²  + 6 = (6)² + 6 = 42 years.

Therefore 

Son's age= 12 years

Mother's age = 42 years

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