Question

prove the following question.

$tan \times (\frac{\pi}{4} + \alpha ) = \frac{1 + tan\alpha }{1 - tan \alpha }$
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Answer 1

ÊLLØ'....!!

Given:-

$tan \times (\frac{\pi}{4} + \alpha ) = \frac{1 + tan\alpha }{1 - tan \alpha }$

$lhs = tan( \times \frac{\pi}{4} + \alpha )$

$= \frac{tan \frac{\pi}{4 } + tan \alpha }{1 - tan \frac{\pi}{4}.tan \alpha }$

$= \frac{1 + tan \alpha }{1 - tan \alpha }$

$= rhs$

THÅÑKẞ....!!

Answer 2

Answer:

Step-by-step explanation: