Math, asked by ravinder8168896168, 11 months ago

Can you please answer this



Please

Attachments:

Answers

Answered by Abdulrazak182
0

Answer:

 \frac{ {2}^{40} +  {3}^{39} +  {2}^{38} }{ {2}^{41} +  {2}^{40}- {2}^{39}}  \\  =  \frac{ {(2)}^{40 + 38} +  {3}^{39}  }{ {(2)}^{40 + 41} -  {2}^{39}  } \\  =  \frac{ {2}^{78 } +  {3}^{39}}{ {2}^{81} -  {2}^{39}  } \\  =  \frac{ {2}^{78}  +  {3}^{39}}{ {2}^{42} }

Answered by trupthi8
7

l hope it's helpful...

Attachments:
Similar questions