Math, asked by kcabkcmc, 10 months ago

rationalize the denominator 1 by root 2 + root 3 minus root 5 ​

Answers

Answered by srilogan33
1

Answer:

= 1 / (√2 + √3 + √5)

= 1 / (√2 + √3 ) + (√5 ) * ( √2 + √3 ) -  ( √5 )/( √2 + √3 ) - ( √5 )

= √2 + √3 - √5  / (√2 + √3 ) + ( √5 ) * (√2 +√3 ) - ( √5 )

= √2 + √3 - √5 / ( √2 + √3 )^2 - (√5 )^2

= √2 + √3 - √5 / (2 + 3 + 2√6 - 5 )

= √2 + √3 -√5 / 5 - 5 + 2√6

= √2 + √3 - √5 / 2√6

= √2 + √3 - √5 / 2√6 * √6 / √6

= √6 (√2 + √3 - √5 ) / 2√6 *√6

= √12 + √18 - √30 / 2 * 6

= √12 + √18 - √30 / 12

i hope that this will help u........................^_^

Step-by-step explanation:

Similar questions