Math, asked by RishkrithBairy, 1 year ago

can you please send me the answer

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Answered by indianguy1

1

sec0-tan0=a+1/a-1
therefore
sec0+tan0=a-1/a+1
solving both equation
2sec0=a-1/a+1+a+1/a-1
sec0=a^2+1/a^2-1
therefore
cos0=a^2-1/a^2+1

Answered by dubeydivya560

1

Answer:

idk

gn

Step-by-step explanation:

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