can you please solve it for me
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coordinates of p:(4,-3)
coordinates of Q:(-2,-2)
coordinate of R:(2,0)
coordinates of Q:(-2,-2)
coordinate of R:(2,0)
Alexajupe:
thanks
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Coordinate of P= (4,-3)
Coordinate of Q= (-2,-2)
Coordinate of R= (2,0)
Slope of QR= Slope of line through P
Therefore, Slope of line through P= -2-0/2+2= -2/4= -1/2
Then, using the equation of line formula u will get=
(y+3)= m(x-4)
(y+3)= -1/2(x-4)
2y+6= -x+4
2y+x+2=0
Coordinate of Q= (-2,-2)
Coordinate of R= (2,0)
Slope of QR= Slope of line through P
Therefore, Slope of line through P= -2-0/2+2= -2/4= -1/2
Then, using the equation of line formula u will get=
(y+3)= m(x-4)
(y+3)= -1/2(x-4)
2y+6= -x+4
2y+x+2=0
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