Question

can you please solve this​

Answer 1

Answer:

$\huge\small\red{ solution }$

$\frac{2}{3x + 6} = \frac{1}{6} - \frac{1}{2x + 4} \\ \\ \frac{2}{3x + 6} + \frac{1}{2x + 4} = \frac{1}{6} \\ \\ \frac{2(2x + 4) + 1(3x + 6)}{(3x + 6)(2x + 4)} = \frac{1}{6} \\ \\ \frac{4x + 8 + 3x + 6}{6x + 12x + 12x + 24} = \frac{1}{6} \\ \\ \frac{7x + 14}{30x + 24} = \frac{1}{6}$

cross multiplication

$6(7x + 14) = (30x + 24) \\ \\ 42x + 84 = 30x + 24 \\ \\ 42x - 30x = 24 - 84 \\ \\ 12x = - 60 \\ \\ x = \frac{ - 60}{12} \\ \\ x = - 5$

Answer 2

Answer:

YES I can, can you tell me which class question is this?