can you please solve this problem
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8^x*4^y=128 ;9^2x-y=1
(2^3)^x*(2^2)^y=2^7 ;2x-y=2^0
3x+2y=7
2x-y=0
solving two equations we get x=1 and y=2
(2^3)^x*(2^2)^y=2^7 ;2x-y=2^0
3x+2y=7
2x-y=0
solving two equations we get x=1 and y=2
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x=1,y=2. hence proved
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