Question

can you plz find it ​

Answer 1

Answer:

$( \frac{27}{64} ) {}^{ \frac{ - 2}{3} }$

$\frac{ {27}^{ \frac{ - 2}{3} } }{ {64}^{ {}^{ \frac{ - 2}{3} } } }$

$\frac{ {3}^{ - 2} }{ {4}^{ - 2} }$

$\frac{16}{9}$

$1 \frac{7}{9}$

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Answer 2

Step-by-step explanation:

(27/64)^(-2/3)

27 = 3^3. 64 = 4^3

= (3^3/4^3)^ (-2/3)

= (3/4)^ (-2/3 × 3)

= (3/4) ^ (-2)

= (4/3) ^(2)

= 16/9 ANSWER

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