Question

Can you prove that ​

Answer 1

yes of course

chliye Suru karte hai

kon he itna thanks

solution:

L.h.s

(sinx+cosx){(cosx/sinx)+(sinx/cosx)}

=(sinx+cosx)(cos^2x+sin^2x/sinxcosx)

as we know cos^2x+sin^2x=1

so

=(sinx+cosx)1/sinxcosx

=sinx+cosx/sinxcosx

=1/cosx+1/sinx

=cosecx+secx

it can't be equal tan x bye

Answer 2

(Sinθ+cosθ)(cos^2θ + sin^2θ/sinθcosθ).............by lcm

(Sinθ+cosθ) (1/sinθcosθ)

Sinθ+cosθ/sinθcosθ

Sin/sinθcosθ +cos/sinθcosθ

Sinθ/cosθ

=tan θ