Question

Velocity of an electron in the 2nd stationary orbit of hydrogen atom is

Answer 1

Bohr radius of nth orbit is,

r_n= .529×n^2/z where z=atomic no;

n=no.of orbit

=>.85×10^-9m=.529×10^-10n^2/z(=1)

We got, n=4

Since, V=2.165×10^6×z/n

=2.165×10^6×1/4

=541250m/s

this way you can find of 2nd stationary orbit also