Velocity of an electron in the 2nd stationary orbit of hydrogen atom is
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Bohr radius of nth orbit is,
r_n= .529×n^2/z where z=atomic no;
n=no.of orbit
=>.85×10^-9m=.529×10^-10n^2/z(=1)
We got, n=4
Since, V=2.165×10^6×z/n
=2.165×10^6×1/4
=541250m/s
this way you can find of 2nd stationary orbit also
r_n= .529×n^2/z where z=atomic no;
n=no.of orbit
=>.85×10^-9m=.529×10^-10n^2/z(=1)
We got, n=4
Since, V=2.165×10^6×z/n
=2.165×10^6×1/4
=541250m/s
this way you can find of 2nd stationary orbit also
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