Question

can you simplify my question

Answer 1

Hey mate! here's your answer!

since, bases are same , and division is there, so we will subtract the exponents.

therefore,


$\frac{{m}^{4} - 1}{ {m}^{2} - 1}$

$= {(m})^{4 - 2} - ({1)}^{1 - 1}$

$= {m}^{2} - ({1})^{0}$

$= {m}^{2} - 1$


hope it is helpful ✌️!

Answer 2

$\dfrac{m^4 - 1}{m^2 - 1}$

write is the form a² - b²:

$=\dfrac{(m^2)^2 - 1^2}{m^2 - 1}$

Apply a² - b² = (a + b) (a - b):

$=\dfrac{(m^2- 1) ( m^2 + 1)}{m^2 - 1}$

Cancel off common factor m² - 1:

$= m^2 + 1$