Question

can you solve it..
If, A+B+C =6
A X B =2
B X C =6

Then C X A = ?

Answer 1

1.) A x B = 2
so, let A be 1and B be 2
then, 1*2=2
2.) B x C = 6
as in 1st, B is 2 and let C be 3
Then, 2*3=6
so, in
3.) C x A = ?
by 1&2 C = 3 and A = 1
then, 3*1 = 3

Proof :-
A+B+C=6
1+2+3= 6
6=6

hope it helps : )
Plz mark it as brainliest.

Answer 2

A+B+C =6 (i)
AB        =2 (ii)
BC        =6 (iii)

From equation (ii)
A=2/B and
From equation (iii)
C=6/B
Put value of A and C in equation (i)
2/B + B + 6/B =6
Multiply with B on both side
2    + B^2 + 6 =6B
8 + B^2 - 6B  = 0
B^2 - 6B + 8  = 0
Let's factorize it:
B^2-4B-2B+8= 0
B(B-4)-2(B-4)=0
(B-2)(B-4)     =0
so B=2 or B=4

By putting these values in equation (ii) and (iii)
A=1 or A= 1/2
C=3 or 3/2
So,
CxA=1x3=3 or CxA=1/2 x 3/2=3/4
In either case, the condition of A+B+C=6 is satisfied