A wooden cylinderical pole is 7 m high and its base radius is 10cm. Find its weight if the wood weighs225 kg per cubic
bawejaesha02:
Per cubic meter?
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Answered by
3
volume of pole =πr^2.h
=22/7 x (10/100)^2 x 7
=22 x 1/100 m^3
now ,
weight of pole=volume x density
=22/100 x 225
=4950/100=49.5 kg
=22/7 x (10/100)^2 x 7
=22 x 1/100 m^3
now ,
weight of pole=volume x density
=22/100 x 225
=4950/100=49.5 kg
Answered by
0
The volume of the cylinder=πr²h.
Height of pole= 10 cm=0.1m
⇒22/7 × 0.1×0.1×7
=22×0.01 = 0.22 m³ = 220000 cm³
Now ,multiply the weight of the wood per cubic meter or centimeter(because you have not mentioned it) to the corresponding volume (m³ or cm³) and you will get the answer.
Height of pole= 10 cm=0.1m
⇒22/7 × 0.1×0.1×7
=22×0.01 = 0.22 m³ = 220000 cm³
Now ,multiply the weight of the wood per cubic meter or centimeter(because you have not mentioned it) to the corresponding volume (m³ or cm³) and you will get the answer.
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