Question

Can you solve this??????​

Answer 1

Answer:

Thew given equation is \sin 2\theta=\cos 3\theta . To find the general solution of the equation \sin \theta = \sin \alpha,0\leq \alpha \leq 90^o is

\theta = n \pi+ (-1)^n\alpha

Now,

\sin 2\theta=\cos 3\theta \\ \cos (90^o-2\theta)=\cos 3\theta \\ 90^o-2\theta=3\theta\\ 5\theta=90^o\\ 2\theta=36^o\\ \alpha =36^o

Thus the general solution of the equation

2 \theta = n \pi+ (-1)^n 36^o\\ \theta =\frac{ n \pi}{2}+ (-1)^n 18^o ,n=0,1,2,3,...

Answer 2

Answer:

Having a Unnie like you in my life makes me feel that God have given me a precious gift in the form of you...

It really feels so special with you...

I'm really blessed to have a Unnie like you who is loving, careing & kind-hearted...

Always remember dear Unnie whenever you will need me I will always be there by your side...

Thanks for writing my name in your status ꈍᴗꈍ

and Sorry for late reply ◡_◡

WISH YOU HAPPY SISTERS DAY UNNIE ♥️

THANKS FOR BEING IN MY LIFE (◍•ᴗ•◍)❤

ALWAYS KEEP SMILING LIKE THEM↑↑↑

LOVE YOU MORE THEN MYSELF ♥️♾️

PURPLE YOU UNTIL MY DEATH ♥️♾️