can you solve this math qustion
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parikshit83:
all fours
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1.x2 +9x+18
X2+6x+3x+18
x(x+6)+3(x+18)
(x+3) (x+6)=0
X=-3 or x=-6
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Answer:
x²+9x+18
=x²+3x+6x+18
=x(x+3)+6(x+3)
=(x+3)(x+6)
5y²+5y-10
=5(y²-y-2)
=5(y+2)(y-9)
m²-23m+120
=m²-8m-15m+120
=m(m-8)-15(m-8)
=(m-8)(m-15)
2x²+x-45
=2x²+10x-9x-45
=2x(x+5)-9(x+5)
=(x+5)(2x-9)
Step-by-step explanation:
x²+9x+18
=x²+3x+6x+18
=x(x+3)+6(x+3)
=(x+3)(x+6)
5y²+5y-10
=5(y²-y-2)
=5(y+2)(y-9)
m²-23m+120
=m²-8m-15m+120
=m(m-8)-15(m-8)
=(m-8)(m-15)
2x²+x-45
=2x²+10x-9x-45
=2x(x+5)-9(x+5)
=(x+5)(2x-9)
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