can you solve this question
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no I am unable to do because I am in class 9
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Step-by-step explanation:
RHS=(cosec A+cot A)²
=[(1/sin A) - (cos A/sin A)]²
/*
1) cosec A= 1/sin A
2) cot A =cos A/sin A */
=[ (1-cosA /sin A]²
=(1+cos A)²/sin²A
=(1-cosA)²/(1-cos ² A)
/*
Sin²A=1-cos²A */
=(1-cos A)² /[(1+cos A) (1-cos A)
/* we know the algebraic identity
a²-b²=(a+b) (a-b) */
After cancellation we get
=(1-cosA) /(1+cos A)
=RHS
Therefore
(cosec A- cot A)²=(1-cosA) /(1+cos A)
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