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Answer:
1/7[-3i - 6j + 2k]
Step-by-step explanation:
Given:
a = 2i + 4j - 5k ----- (1)
b = i + j + k ----- (2)
c = j + 2k.
Now,
a + b + c = 2i + 4j - 5k + i + j + k + j + 2k
= 3i + 6j - 2k
|a + b + c| = √3² + 6² + (-2)²
= √49
= 7.
So, the unit vector in the direction of a + b + c = (1/7)[3i + 6j - 2k].
Therefore, the unit vector in the opposite direction = (1/7)[-3i - 6j + 2k]
Hope it helps!
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