Math, asked by harshkumar4816, 1 year ago

Can you solve this question Mr brain

Attachments:

amitnrw: Sin a /(sec a + tan a -1) + cos a /(cosec a+ cot a -1)
= Sin a / (1/cos a + sin a / cos a -1 ) + cos a / ( 1/sin a + cos a/ sin a -1)
= Sin a cos a / (1 + sina -cosa) + cosa sina/(1+ cosa - sina)
= SinaCosa(1+sina - cosa + 1+ cosa-sina)/(1^2-(sina-cosa)^2)
= 2Sinacosa/(1 - (si n^2a + cos^2a- 2sinacosa))
= 2sinacosa/(1 - (1 - 2sinacosa)
= 2sinacosa/ 2sinacosa
= 1
Qed

Answers

Answered by shikayna2345

SinA/secA+tanA-1+cosA/cosecA+cotA-1
=sinA/(1/cosA+sinA/cosA-1)+cosA/(1/sinA+cosA/sinA-1)
=sinA/{(1+sinA-cosA)/cosA}+cosA/{(1+cosA-sinA)/sinA}
=sinAcosA/(1+sinA-cosA)+sinAcosA/(1+cosA-sinA)
=sinAcosA[(1+cosA-sinA+1+sinA-cosA)/(1+sinA-cosA)(1+cosA-sinA)]
=2sinAcosA/(1+sinA-cosA+cosA+sinAcosA-cos²A-sinA-sin²A+sinAcosA)
=2sinAcosA/{1+2sinAcosA-(sin²A+cos²A)}
=2sinAcosA/(1+2sinAcosA-1)
=2sinAcosA/2sinAcosA
=1 (Proved)

Hope this will help u
and plzzz Mark me as a brainlist.......

Answered by amitnrw

Answer:

Step-by-step explanation:

Sin a /(sec a + tan a -1) + cos a /(cosec a+ cot a -1)

= Sin a / (1/cos a + sin a / cos a -1 ) + cos a / ( 1/sin a + cos a/ sin a -1)

= Sin a cos a / (1 + sina -cosa) + cosa sina/(1+ cosa - sina)

= SinaCosa(1+sina - cosa + 1+ cosa-sina)/(1^2-(sina-cosa)^2)

= 2Sinacosa/(1 - (si n^2a + cos^2a- 2sinacosa))

= 2sinacosa/(1 - (1 - 2sinacosa)

= 2sinacosa/ 2sinacosa

= 1

Qed

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