can you tell the answer of 8th qn.
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Answer is in the attachment.....
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suvethal07:
This is which identity
I think this answer is incorrect
hii
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Answer:(x+2)(x^2-1)(x^2-4)
Step-by-step explanation:
(x^2+x-2)(x^2-x+2)
[x^2+2x-x-2][x^2-2x+x+2]
[x(x+2)-1(x+2)][x(x-2)+1(x+2)]
(x-1)(x+2)(x+1)(x-2)(x+2)
(x+2)[(x^2)-(1^2)][(x^2)-(2^2)]
(x+2)(x^2-1)(x^2-4)
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