Question

Capacitor of 1uf is connected to a 60v battery it is then connected to a 2uf capacitor find the final charge

Answer 1

From Q=CVQ=CV The total charge in the system is the sum of charges in the individual capacitors. So Q1=10mCQ1=10mC and Q2=2mCQ2=2mC. But now these charges will redistribute themselves in the capacitors so that the voltage across each capacitor is the same.

If V′V′ is the new voltage across each capacitor, the new charges will be Q′1=C1V′Q1′=C1V′ and Q′2=C2V′.Q2′=C2V′.

Since the total charge in the system has not changed, Q′1+Q′2=12mC.Q1′+Q2′=12mC.

Solving for V′,V′,

V′(C1+C2)=QV′(C1+C2)=Q

V′=400VV′=400V



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