Triangles ABC and DBC are on the same base BC with vertices A and D on Opposite sides of BC such that ar (ABC) =ar (DBC). Show that BC bisects AD .
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Note:-
Pic 1 = Classes below 10
Pic 2 and 3 = For class 10
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See the pic ↓↓↓
Pic 1 = Classes below 10
Pic 2 and 3 = For class 10
☺ Hope this Helps ☺
See the pic ↓↓↓
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nitthesh7:
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if u r class 10 do only the pic 2 and 3 as it is based on 10th portions.☺
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Answer:
in the adjoining figure triangle ABC and triangle DBC are on the same base BC with a n d on opposite sides of BC such that area of triangle ABC equal to area of triangle DBC so that BC bisects ad
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