capacitors of capacities 5f and 10f are connected in parallel in a circuit with the cell of emf 2v. what should be the capacity of the capacitors to be connected in series with parallel combination to get 1 coulomb charge of flow in a circuit
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Answer:
Capacitance =Q/v
Explanation:
C=1/15F. C=0.66F
in series case C=0.333F
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