Capacity of a parallel capacitor with dielectric constant 5
is 40uF. Calculate the capacity of the same capacitor when
dielectric material is removed.
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7
Answer:
When a dielectric constant is present, capacitance is given by
C' = C × k
C' = 40 uF ( Since dielectric is present)
When dielectric is removed, capacitance reduces by a factor of k
C = C' / k
= 40uF / 5
= 8 uF
Explanation:
When dielectric is removed general trick is to divide the capacitance by dielectric constant :)
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