Question

Car a is travelling at a speed 60 km/h and b with speed 42 km/h each car being 5 m long.Find distance to be overtaked

Answer 1

$\huge\underline\orange{\mathcal Answer}$

$\large\blue{\boxed{Overtake\:Distance=38.3m}}$

$\huge\underline\orange{\mathcal Solution}$

Car A speed = 60km/hr

Convert it into metre per second

$\large{Car\:A\:Speed=60\times{\frac{5}{18}}m/s}$

Car B speed = 42 km/hr

Convert it into metre per second

$\large{Car\:B\:Speed = 42\times{\frac{5}{18}}m/s}$

Relative Speed of Car A w.r.t Car B is :-

$\large{=> {\frac{50}{3}}-{\frac{35}{3}}=5m/s}$

$\large{Time = {\frac{Distance}{Speed}}}$

$\large{Time = {\frac{10}{5}}}$

$\large{\boxed{Time(t)=2s}}$

Total distance for overtake = Distance covered by car in overtaking+ length of car

$\large{=> {\frac{50}{3}}\times 2 + 5}$

$\large{=> {\frac{100}{3}}+5}$

$\large{=> 33.3 + 5}$

$\large{\boxed{Total\:Dist.\:Of\:Overtaking=38.3m}}$

Answer 2

Answer is 38.3 m

Hope this will help