Question

car A takes  1 hour less than car B to cover a distance of 132 km. if the average  speed of car A
is 11km/hr more than  that of car B, formulate the  quadratic equation

Answer 1

Let average speed of car B = x km/h
      average speed of car A = (x+11) km/h

To cover 132 km, 
time taken by car B = 132/x hours
time taken by car A = 132/(x+11) hours

Now 
$\frac{132}{x}$ - $\frac{132}{x+11}$ = 1
⇒132($\frac{1}{x}$ - $\frac{1}{11+x}$) = 1
⇒132($\frac{-x+(x+11)}{x(x+11)}$) = 1
⇒132($\frac{11}{x(x+11)}$) = 1
⇒$\frac{132(11)}{x^2+11x}$ = 1
⇒x² + 11x = 1452
⇒x² + 11x -1452 = 0

Answer 2

the avg speed of B be x
then the avg speed of A=x+11

the distance covered=132 km
 time taken by A=132/(x+11)
time taken by B=132/x
 ATQ ,
(132/x)-132/(x+1)=1
$\frac{132}{x} - \frac{132}{x+11} =1$
solving this we will get
x²+11x=1452
⇒x²+11x-1452=0
which is the required quadratic eqn