Physics, asked by arpitaakansha20, 7 months ago

car acceleration from rest at constant acceleration 6 m/s2 for some time after which it decelerates atconstant rate 3 m/s2 to come to rest. If the total time is 15 sec. Find maximum velocity reached by car? Pls answer asap

Answers

Answered by vbhanuprasad
1

Answer:

20 velocity reached by car

Answered by jainlalita610
1

Answer:

Explanation:

Suppose car acceleration for time t. So it decelerate by time (15−t)s.

Initially at rest, u=0 and come to velocity v in time t! use from Kinematics  

for constant accim, (a=10m/m  

2

)  

⇒ v=⊥0t →(1)

⊥ & (2) gives,

⊥Ot=5(15−t) ⇒ t=5 s.

for constant deceleration (a=−5m/s)

⇒ o=v−5(15−t)

⇒ v=5(15−t) →(2)

so, v=⊥ot=50 m/s

construct a v−t graph from obtained results.

From graph

(i) max velocity =50 m/s

(ii) net distance travelled =area ot vt graph

d=  

2

1

​  

×50×15=375 m

∴ average velocity =  

t

d

​  

=  

15

375

​  

=25 m/s

during deceleration distance travelled, d  

1

​  

=  

2

1

​  

×(15−5)×50=250m

∴ avg velocity during deceleration =  

Δt

d  

2

​  

 

​  

=  

(15−5)

250

​  

=25 m/s

solution

Similar questions