Question

car has a uniform acceleration of 2.5 ms^-2. calculate the distance traveled by the car after 10 second of start?​

Answer 1

Answer:

125 m

Explanation:

According to the given question,

a = acceleration = 2.5 m/s^2

u = initial velocity = 0 m/s

t = time = 10 sec

s = displacement = ?

And we are asked to find the distance in the given conditions.

Here, distance is equal to displacement as it's a linear motion without changing direction.

Now, we know

• s = ut + 1/2 at^2

Putting the values we get

• s = 1/2 × 2.5× 100

• s = 50×2.5

• s = 5×25

• s = 125 m

Thus distance covered by the car in 10 sec is 125m if acceleration is 2.5 m/s^2 and initial velocity is 0 m/s.