car initially at rest starts with A uniform acceleration and gains a velocity of 20 m per second in 4 seconds The displacement of the car is
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Answered by
25
u = 0m/s as it is at rest
v = 20m/s (given)
t = 4 secs
First,
v=u+at
20 = 0 + 4a
a = 20/4
= 5m/s^2
Now,
s = ut + 1/2at^2
= 0 + 1/2*5*4*4
= 5*4*2
= 40 m
v = 20m/s (given)
t = 4 secs
First,
v=u+at
20 = 0 + 4a
a = 20/4
= 5m/s^2
Now,
s = ut + 1/2at^2
= 0 + 1/2*5*4*4
= 5*4*2
= 40 m
Answered by
8
u= 0m/s
v= 20m/s
t= 4s
a= v2-v1/t= 5m/s^2
s= ut+1/2at^2
s=0+1/2×5×4×4
∴s=40m
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