Question

write the Pythagorean triplet whose leat no is 18

Answer 1

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Answer 2

1) 18

$genaral \: form =$

2m, m^2-1, m^2+1

$2m = 18 \\ \: m = 18 \div 2 \\ \: m = 9 \\ \\ m { }^{2} - 1 = 9 - 1 = 8 \\ \\ m {}^{2} + 1 = 9 - 1 = 10$
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