Question

car is
A brought to rest after 10 seconds initially
moving with 9 kmph. The mass of the car is 2000 kg.
Calculate the retarding force acting on the car​

Answer 1

Given:-

• Initial velocity ,u = 0m/s

• Time taken , t = 10s

• Final velocity ,v = 9km/h

• mass of the car ,m = 2000kg

To Find:-

• Retardation Force (F).

Solution:-

Converting the unit here

Final velocity =9km/h = 9×5/18 = 45/18

Firstly we calculate the acceleration of the car

As we know that rate of change of velocity at per unit time is called acceleration.

→a = v-u/t

Substitute the value we get

→ a = 45/18 - 0 /10

→ a = 45/28/10

→ a = 45×10/28

→ a = 450/28

→ a = 16.07 m/s²

∴ The acceleration of the car is 16.07 m/s²

Now we know that Force is the product of mass and acceleration

→F = m×a

Substitute the value we get

→ F = 2000 × 16.07

→ F = 32140N

∴ The retardation force acting on the car is 32140 Newton.

Answer 2

Answer:

321049 p

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