Car is passing through a convex bridge. If the radius of the bridge is 40m, what velocity should the car have at center of the bridge to have centripetal acceleration equal to gravitational acceleration?
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Centripetal acceleration = v^2/R
R = 40m and v we need to find out.
v^2/R = g
v^2 = Rg = 400
v = 20m/s
Hence the car should travel with this velocity at the centre
R = 40m and v we need to find out.
v^2/R = g
v^2 = Rg = 400
v = 20m/s
Hence the car should travel with this velocity at the centre
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