Question

car is travelling at a velocity of 72km/hr, if its velocity increases to 90 km/hr in 5 seconds, find its acceleration *​

Answer 1

Answer:

INITIAL VELOCITY = U = 54 km/h = 15 m/S

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/s

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDS

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*5

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*55A = 20 - 10

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*55A = 20 - 105A = 10

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*55A = 20 - 105A = 10A = 10/5

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*55A = 20 - 105A = 10A = 10/5A = 2 m/s2

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*55A = 20 - 105A = 10A = 10/5A = 2 m/s2THEREFORE,

INITIAL VELOCITY = U = 54 km/h = 15 m/SFINAL VELOCITY = V = 72 km/h = 20 m/sTIME = T = 5 SECONDSFINDING ACCELERATION (A)------------------------------------------V = U + AT. (FIRST EQ. OF MOTION)20 = 10 + A*55A = 20 - 105A = 10A = 10/5A = 2 m/s2THEREFORE,ACCELERATION = 2 m/s2

Answer 2

Explanation:

U= 72 = 20m/s

V= 90 = 25 m/s

t = 5 s

v = u+at

v-u/T = a

25 - 20 / 5 = a

thus

a=1 m/s²