Math, asked by nikhil200727, 10 months ago

car moves with the speed of 40 km per hour for 15 minute and then with a speed of 60 km per hour in the next 15 minutes find the total distance covered by the car in this 30 minutes ​

Answers

Answered by rahulsaini1698
0

Answer:

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Answered by ƦαíηвσωStαƦ
5

{\purple{\underline{\underline{\bf{\pink{Solution:-}}}}}}

\mathfrak{\underline{AnswEr:-}}

  • The total distance covered by the car in these 30 minutes = 25 km

\mathfrak{\underline{Given:-}}

  • A car moves with the speed of 40 km/hour for 15 minutes and then with a speed of 60 km/hour in the next 15 minutes.

\mathfrak{\underline{Need\:To\: Find:-}}

  • The total distance covered by the car in these 30 minutes = ?

{\purple{\underline{\underline{\bf{\pink{Explanation:-}}}}}}

1st Distance:

  • Speed = 40km/hour

  • Time = 15 minutes

  • Time = \mathsf {\dfrac{\cancel{15}}{\cancel{60}}\:}

  • Time = \mathsf {\dfrac{1}{4}\:hour}

\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}

\bigstar{\underline{\boxed{\sf\purple{Distance = Speed \times Time}}}} \\\\

\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}

\longrightarrow \sf {Distance = 40 \times \dfrac{1}{4}} \\\\

\longrightarrow \sf {Distance = 10\:km} \\\\

\rule{200}{2}

2nd Distance:

  • Speed = 60km/hour

  • Time = 15 minutes

  • Time = \mathsf {\dfrac{1}{4}\:hour}

\:\:\:\:\dag\bf{\underline \green{Formula\:used\:here:-}}

\bigstar{\underline{\boxed{\sf\purple{Distance = Speed \times Time}}}} \\\\

\:\:\:\:\dag\bf{\underline \blue{Putting\:the\:values:-}}

\longrightarrow \sf {Distance = 60 \times \dfrac{1}{4}} \\\\

\longrightarrow \sf {Distance = 15\:km} \\\\

\rule{200}{2}

\:\:\:\:\dag\bf{\underline \green{As\:we\:know\:that:-}}

\bigstar{\underline{\boxed{\sf\purple{1st \: distance + 2nd\: distance}}}} \\\\

\longrightarrow \sf {Total \:distance = 15 + 10} \\\\

\longrightarrow \sf {Total\: distance = 25\:km} \\\\

\:\:\:\:\dag\bf{\underline{\underline \blue{Hence:-}}}

  • The total distance covered by the car in these 30 minutes = 25 km

\rule{200}{2}

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