Question

car moving at a velocity of 72 km per hour brakes are applied to so as to stop the car at a distance of 10 metre find the retardation produce in the car​

Answer 1

Answer:

-259.2 m/s²

Explanation:

given that,

velocity at which car is moving = 72km/h

when break applied,

car stop after distance = 10 meter

so,

here,

initial velocity(u) of a car = 72Km/h

final velocity(v) = 0 m/s [car stops]

distance(S) travelled by car after appliying brakes = 10 meter

by the equation of motion ,

v² = u² + 2aS

where,

a = acceleration

so,

now,

According to the question and equation of motion

putting the values as,

v = 0 m/s

u = 72 m/s

s = 10 m

a = acceleration

➡(0)² = (72)² + 2a(10)

➡20a + 5184 = 0

➡20a = -5184

➡a = -5184/20

✔a = -259.2 m/s²

negation shows the retardation

so,

Retardation of car = -259.2 m/s²