Question

car moving with a speed of 36 kilometre per hour​

Answer 1

Answer:

v=velocity of car =36k ×m/h× r=10m/sec

r=radius of ∘a−−r path=50m

μ= mass of small body =100 gj=0.1 kg u=friction coefficient between plant & body

=0.58

a. The normal contact force exerted by the plant on the block

N=mv^2/r

=o.1 ×100/50=1/5=0.2N

b. The plate is turned so the angle between the normal to the plate and the radius of the rod slowly increases

N=mv^2/r ×cosθ (i)

μN=mv^2/rsinθ (ii)

putting value of N from i l t br.

μmv^2/rcosθ=mv^2/rsinθ

r ar r mu=tan theta r a r r theta=tan^-1(0.58)=30^0`

Explanation: