Question

factorise (a+b)3 - 3ab (a+b)

Answer 1

Factorize a^3 + b^3 -1 +3ab 

As we know, 

a^3+b^3+c^3−3abc=(a+b+c)(a^2+b^2+c^2−ab−bc−ca) 

Here c=-1 

a^3 + b^3 +(-1)^3-3ab(-1)=(a+b-1)(a^2-ab+a+b^2+b+1)

Answer 2

Answer:

Factorize a^3 + b^3 -1 +3ab  

As we know,  

a^3+b^3+c^3−3abc=(a+b+c)(a^2+b^2+c^2−ab−bc−ca)  

Here c=-1  

a^3 + b^3 +(-1)^3-3ab(-1)=(a+b-1)(a^2-ab+a+b^2+b+1)

Step-by-step explanation: