car of 2000 kg accelarates to cover 40m in 6 sec work done is
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The work done on a body is always the change in its kinetic energy (final - initial).
Now, as the car was at rest then the initial kinetic energy is zero, so the work done will be
W = KE = (1/2)mv2
here m = 1200 kg
and v = distance/time
= 40/5 = 8 m/s
so, the
W = (1/2) X 1200 X (8)2 = 38400 J
Now, as the car was at rest then the initial kinetic energy is zero, so the work done will be
W = KE = (1/2)mv2
here m = 1200 kg
and v = distance/time
= 40/5 = 8 m/s
so, the
W = (1/2) X 1200 X (8)2 = 38400 J
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