Question

car travelling at 20 m/s is to be brought to rest in a distance of 200 m, then its retardation should be :

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Answer 1

Answer:

We have ,

u=20, v=0, s=200

Now by applying

v²-u²=2as

0-20²=2a200

-400=400a

a= -1 ANS

Answer 2

Explanation:

Initial velocity=20m/s

Final velocity=0m/s(because it is brought to rest)

Distance=200m

Using third equation of motion

v²=u²+2as

0²=20²+2a*200

0=400+400a

-400=400a

a =-400/400

a=-1ms-²