Question

Car travelling at 36 km/hr due north turms west in 5 sec and maintains the same speed . Find the average accelaation of car in m/s^2 with direction..

Answer 1

 Initial velocity = 36 j^ km/hr (as car is travelling 36 km/hr due north)
Final velocity = -36 i^ km/hr
Change in velocity vector = vfinal - vinitial
                                    = -36 i^ - 36 j^ = -36(i^ + j^) {So, direction is South-West}
| ΔV vector| = √(36^2 + 36^2)
                   = √2 * 36 km/hr
                    = √2 * 36 * 5/18 m/sec
                     = 10√2 m/sec
Accelaration of the car = | ΔV vector| /Δt = 10√2 / 5 = 2√2 m/sec (South-west)