car travelling at certain speed V1 overtakes another car travelling at a slower speed V2 at A. an hour later the faster car reverses it's direction change its speed to v3 and after sometime meet the slower car now coming in the opposite direction at position B.the distance between the position A and B is 10 km .find the speed of the slower car if V1-v2=v3+v2
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The total distance driven = [(2 h )(40 km /h) + (2 h)( 60 km/h)] = 200 km
The total time = 2 + 2 = 4 h
average speed = (200 km)/(4 h) = 50km/h
b. total distance = 100 + 100 = 200 km
total time = [(100 km)/(40 km/h) + (100 km)/ 60 km/h)] = 4.17 h
average speed = (200 km)/(4.17 h) = 48 km/h
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v2=5 kmph
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